MCQ
On charging the lead accumulator cell :
- A$PbO _2$ dissolves
- B$PbSO _4$ deposits on the lead electrode
- ✓$H _2 SO _4$ is formed again
- DThe amount of $H _2 SO _4$ is less
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.



