MCQ
On electrolysing a solution of dilute ${H_2}S{O_4}$ between platinum electrodes, the gas evolved at the anode is
- A$S{O_2}$
- B$I{F_5}$
- ✓${O_2}$
- D${H_2}$
✓
Answer
Correct option: C.
${O_2}$
c
(c)In between dilute ${H_2}S{O_4}$ and platinum electrode ${O_2}$ gas evolve at anode.
(c)In between dilute ${H_2}S{O_4}$ and platinum electrode ${O_2}$ gas evolve at anode.
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List $II$ (Number of Faraday required) |
| $A$. $1 \mathrm{~mol}$ of $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$ | $l$. $3 \mathrm{~F}$ |
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Choose the correct answer from the options given below: