- A$N{H_4}N{O_3}$
- ✓${N_2}$
- C${N_2}O$
- D$NO$
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$(I)$ Only compounds with chiral centers can be optically active
$(II)$ Absence of elements of symmetry is the reason for a molecule's optical activity
$(II)$ All organic compounds contain carbon & hydrogen
$(IV)$ Different cannonical forms of a molecule represent the actual structures of a molecule which has resonace in it

$\frac{{ - d\left[ {{N_2}{O_5}} \right]}}{{dt}} = k\left[ {{N_2}{O_5}} \right]$ ,
$\frac{{d\left[ {N{O_2}} \right]}}{{dt}} = k'\left[ {{N_2}{O_5}} \right]$,
$\frac{{d\left[ {{O_2}} \right]}}{{dt}} = k''\left[ {{N_2}{O_5}} \right]$
The relationship between $k$ and $k'$ and between $k$ and $k^{"}$ are
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - H}
\end{array}$ $\mathop {\xrightarrow{{HCN}}}\limits_{\mathop O\limits^\Theta H} (A)\mathop {\xrightarrow{{{H_2}O/{H^ \oplus }}}}\limits_\Delta $ Product
Product will be :