- ✓$N_2$ in both cases
- B$N_2$ with ammonium dichromate and $NO$ with barium azide
- C$N_2O$ with ammonium dichromate and $N_2$ with barium azide
- D$N_2O$ with ammonium dichromate and $NO_2$ with barium azide
$\left( NH _4\right)_2 Cr _2 O _7 \rightarrow Cr _2 O _3+4 H _2 O + N _2$
$Ba \left( N _3\right)_2 \rightarrow Ba +3 N _2$
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$\mathrm{MnO}_2+\mathrm{KOH}+\mathrm{O}_2 \rightarrow \mathrm{A}+\mathrm{H}_2 \mathrm{O} .$
Product ' $A$ ' in neutral or acidic medium disproportionate to give products ' $\mathrm{B}$ ' and ' $\mathrm{C}$ ' along with water. The sum of spin-only magnetic moment values of $B$ and $C$ is . . . . . .$BM$. (nearest integer)
(Given atomic number of $\mathrm{Mn}$ is $25$ )

$CHCl_3\xrightarrow[hv]{O_2}[A]\xrightarrow{EtOH}[B]\xrightarrow{2\ mole\ MeMgBr}$
$[C]\xrightarrow{CaOCl_2}[D]\xrightarrow{\Delta}CH_3-\underset{\underset{O}{||}}{C}-CH_3$
[Assume : No cyano complex is formed; $K _{ sp }( AgCN )$ $=2.2 \times 10^{-16}$ and $\left. K _{ a }( HCN )=6.2 \times 10^{-10}\right]$