MCQ
On heating $NaNO_3$ gives
- ✓$O_2$
- B$NO_2$
- C$O_2 + NO_2$
- D$Na_2O$
✓
Answer
Correct option: A.
$O_2$
a
$NaN{O_3}\xrightarrow{\Delta }NaN{O_2} + \frac{1}{2}{O_2}$
$NaN{O_3}\xrightarrow{\Delta }NaN{O_2} + \frac{1}{2}{O_2}$
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