MCQ
On heating $NaNO_3$ gives
- ✓$O_2$
- B$NO_2$
- C$O_2 + NO_2$
- D$Na_2O$
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$C{H_3}C{H_2}COOH\xrightarrow{{SOC{l_2}}}\,B\,$$ \xrightarrow{{N{H_3}}}\,C\,\xrightarrow[{B{r_2}}]{{KOH}}\,D$
The structure of $D$ would be
Reason : $SO_2$ is a reducing agent