- A$1^\circ$ alcohol
- B$2^\circ$ alcohol
- ✓$3^\circ$ alcohol
- DNone of these
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$\begin{array}{*{20}{c}}
{C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - COOH}
\end{array}\xrightarrow{\Delta }(A)\xrightarrow{{C{H_3} - C{H_2}N{H_2}/\Delta }}(B)$
$(B)$ will be :
$I \frac{\left( CH _3 CO \right)_2 O }{ CH _3 COONa } J \xrightarrow[\begin{array}{l}\text { (ii) } SOCl _2 \\ \text { (ii) anhyd. } AlCl _3\end{array}]{\text { (i) } H _2, Pd / C } K$
$J \left( C _9 H _8 O _2\right)$ gives effervescence on treatment with $NaHCO _3$ and positive Baeyer's test
$1.$ The compound $K$ is
mcq $Image$
$2.$ The compound $I$ is
mcq $Image$
Give the answer question $1$ and $2.$