MCQ
On the intervl $ (1,3)$, the function $f(x) = 3x + {2 \over x}$ is
  • A
    Strictly decreasing
  • Strictly increasing
  • C
    Decreasing in $ (2, 3) $ only
  • D
    Neither increasing nor decreasing

Answer

Correct option: B.
Strictly increasing
b
(b) $f(x) = 3x + \frac{2}{x}$

==> $f'(x) = 3 - \frac{2}{{{x^2}}}$

Clearly $f'(x) > 0$ on the interval $(1, 3)$ 

$f(x)$ is strictly increasing.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$\int \frac{e^x}{x+1}[1+(x+1) \log (x+1)] d x$ equals
$\int_{}^{} {\frac{{\cos x - 1}}{{\cos x + 1}}\;dx = } $
Period of $f(x) = nx + n - [nx + n]$, $n \in N$

where [ ] denotes the greatest integer function is :

If $\vec a = 2\sin \theta \hat i - \hat j + 2\hat k$ , $\vec b = 2\hat i + 2\sin \theta \hat j - \hat k$ and $\vec c = 4\hat i + \hat j + 4\,\,{\cos ^2}\theta \hat k$ are coplanar. Then $\theta $ can be equal to
If $q_1$ , $q_2$ , $q_3$ are roots of the equation $x^3 + 64$ = $0$ , then the value of $\left| {\begin{array}{*{20}{c}}
  {{q_1}}&{{q_2}}&{{q_3}} \\ 
  {{q_2}}&{{q_3}}&{{q_1}} \\ 
  {{q_3}}&{{q_1}}&{{q_2}} 
\end{array}} \right|$ is
The area bounded by the curve y2 = 8x, the x-axis and the lastus rectum is:
  1. $\frac{16}{3}$
  2. $\frac{23}{3}$
  3. $\frac{32}{3}$
  4. $\frac{16\sqrt{2}}{3}$
For every integer $n$, let $a_n$ and $b_n$ be real numbers. Let function $f: I R \rightarrow$ $IR$ be given by $f(x)=\left\{\begin{array}{ll}a_n+\sin \pi x, & \text { for } x \in[2 n, 2 n+1] \\ b_n+\cos \pi x, & \text { for } x \in(2 n-1,2 n)\end{array}\right.$, for all integers $n$.

If $f$ is continuous, then which of the following hold$(s)$ for all $n$ ?

$(A)$ $a_{n-1}-b_{n-1}=0$ $(B)$ $a_n-b_n=1$ $(C)$ $a_n-b_{n+1}=1$ $(D)$ $a_{n-1}-b_n=-1$

If the events $A$ and $B$ are mutually exclusive events such that $P\left( A \right) = \frac{{3x + 1}}{3}$ and $P\left( B \right) = \frac{{1 - x}}{4}$, then the set of possible values of $x$ lies in the interval
Let ${I_1} = \int\limits_0^1 {\frac{{{e^x}}}{{\left( {1 + x} \right)}}} \,dx$ and ${I_2} = \int\limits_0^1 {\frac{{{x^2}}}{{{e^{{x^3}}}\left( {2 - {x^3}} \right)}}} \,dx$ then value of $\frac{{{I_1}}}{{{I_2}}}$ is equal to
A man $ 2 $ metre high walks at a uniform speed  $5$  metre/hour away from a lamp post $ 6$ metre high. The rate at which the length of his shadow increases is