MCQ
One mole of helium is adiabatically expanded from its initial state $\left(P_i, V_i, T_i\right)$ to its final state $\left(P_f, V_f, T_f\right)$. The decrease in the internal energy associated with this expansion is equal to
  • $C_V\left(T_i-T_f\right)$
  • B
    $C_P\left(T_i-T_f\right)$
  • C
    $\frac{1}{2}\left(C_P+C_V\right)\left(T i-T_f\right)$
  • D
    $\left(C_P-C_V\right)\left(T_i-T_f\right)$

Answer

Correct option: A.
$C_V\left(T_i-T_f\right)$
(a)$\Delta U=\mu C_V \Delta T=1 \times C_V\left(T_fT_i\right)=C_V\left(T_i-T_f\right) $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$\mathrm{X}$ - rays and $\gamma$ - rays of the same energies may be distinguished by
The total power content of an AM wave is $900 \mathrm{~W}$. For $100 \%$ modulation, the power transmitted by each side band is
A player caught a cricket ball of mass $150 gm$ moving at the rate of $20 m / sec$. if the catching process be completed in $0.1 sec$ the force of the blow exerted by the ball on the hands of player is
During the adiabatic expansion of $2$ moles of a gas, the internal energy of the gas is found to decrease by $2$ joules, the work done during the process on the gas will be equal to
A coil in the shape of an equilateral triangle of side $10\, {cm}$ lies in a vertical plane between the pole pieces of permanent magnet producing a horizontal magnetic field $20\, {mT}$. The torque acting on the coil when a current of $0.2\, {A}$ is passed through it and its plane becomes parallel to the magnetic field will be $\sqrt{{x}} \times 10^{-5} \,{Nm}$. The value of ${x}$ is ..... .
A gas expands $0.25 \mathrm{~m}^3$ at constant pressure $10^3 \mathrm{~N} / \mathrm{m}^2$, the work done is
Two bulbs are working in parallel order. Bulb $A$ is brighter than bulb $B$. If $R_A$ and $R_B$ are their resistance respectively then
Mass of moon is $7.34 \times 10^{22} \mathrm{~kg}$. If the acceleration due to gravity on the moon is $1.4 \mathrm{~m} / \mathrm{s}^2$, the radius of the moon is $\left(G=6.667 \times 10^{-11} \mathrm{Nm}^2 / \mathrm{kg}^2\right)$
A mercury drop of radius $1 \mathrm{~cm}$ is sprayed into $10^6$ drops of equal size. The energy expended in joules is (surface tension of Mercury is $\left.460 \times 10^{-3} \mathrm{~N} / \mathrm{m}\right)$
Antimony and bismuth are usually used in a thermocouple, because