MCQ
One mole of oxygen gas at STP is equal to _______.
- A6.022 × 1023 molecules of oxygen.
- B6.022 × 1023 atoms of oxygen.
- C16g of oxygen.
- D32g of oxygen.
Explanation:
1 mole of O2 gas at STP = 6.022 × 1023 molecules of O2 (Avogadro number) = 32g of O2. Hence, 1 mole of oxygen gas is equal to molecular weight of oxygen as well as Avogadro number.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
${K_p} = 8 \times {10^{ - 2}}$$C{O_{2(g)}} + {C_{(s)}} \to 2C{O_{(g)}}$ ; ${K_p} = 2$
$CaC{{O}_{3(s)}}\xrightarrow{\Delta }Ca{{O}_{(s)}}+C{{O}_{2}}\uparrow $; ${{K}_{p}}=8\times {{10}^{-2}}$