MCQ
Only an aldehyde having..... can undergo the aldol condensation
  • A
    At least one beta H atom
  • At least one alpha $H$ atom
  • C
    An aromatic ring
  • D
    No alpha H atom

Answer

Correct option: B.
At least one alpha $H$ atom
b
presence of At least one alpha H atom in aldehyde is the necessary condition for aldol condensation.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If ${P^o}$ and $P$ are the vapour pressure of a solvent and its solution respectively and ${N_1}$ and ${N_2}$ are the mole fractions of the solvent and solute respectively, then correct relation is
On heating ammonium dichromate and bariumazide separately we get 
When carboxylic acid reacts with organolithium reagents to give ketones side  reaction sometimes occur. For example,

$\begin{matrix}
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O  \\
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||  \\
   HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}COH  \\
\end{matrix}$ $\xrightarrow[tetrahydro\,\,futan ]{(x)\,\,C{{H}_{3}}Li}$ $\xrightarrow[{{H}_{2}}]{N{{H}_{4}}Cl}$ $\underset{Compound\,\,\,A\,\,63\,\%}{\mathop{\begin{matrix}
   \,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,  \\
   \,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||  \\
   HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}-C-C{{H}_{3}}  \\
\end{matrix}}}\,$ $\underset{37\,\%}{\mathop{+\,\,Compound\,\,(B)}}\,$

Value of $(x)$ in above reaction is

The mass of a substance liberated when a charge '$q$' flows through an electrolyte is proportional to
The final product $'A'$ in the following reaction sequence
The reason for double helical structure of $DNA$ is operation of
An isomer of ${C_3}{H_6}C{l_2}$ on boiling with aqueous $KOH$ gives acetone. Hence, the isomer is
Product of the reaction is
The order of decreasing rate of reaction with ammonia is
Method by which lyophobic sol can be protected.