8.2 Organic chemistry isomerism — Chemistry STD 11 Science — Question

$C{H_3} - C \equiv CH\xrightarrow[{Dry\,ether}]{{C{H_3}MgBr}}C{H_4} + (A)\xrightarrow[{(ii)\,{H_2}O/{H^ + }}]{{(ii)\,C{O_2}}}(B),(B)$ will be

STATEMENT-$2$: All chiral molecules have chiral centres.

$A$. $\mathrm{Be} \rightarrow \mathrm{Be}^{-}$

$B$. $\mathrm{N} \rightarrow \mathrm{N}^{-}$

$C$. $\mathrm{O} \rightarrow \mathrm{O}^{2-}$

$D$. $\mathrm{Na} \rightarrow \mathrm{Na}^{-}$

$E$. $\mathrm{Al} \rightarrow \mathrm{Al}^{-}$

Choose the most appropriate answer from the options given below :

Electron geometry     $-$      Possible molecular shape from respective electron                                                   geometry