MCQ
Outermost electronic configurations of four elements $A, B, C, D$ are given below.

$3 s^{2}$; $3 s^{2} 3 p^{1}$; $3 s ^{2} 3 p ^{3}$; $3 s^{2} 3 p^{4}$

The correct order of first ionization enthalpy for them is.

  • A
    $(A) < (B) < (C) < (D)$
  • $(B) < (A) < (D) < (C)$
  • C
    $( B )<( D )<( A )<( C )$
  • D
    $( B ) < ( A ) < ( C ) < (D)$

Answer

Correct option: B.
$(B) < (A) < (D) < (C)$
b
$3 s ^{2} \rightarrow Mg$

$3 s ^{2} 3 p ^{1} \rightarrow Al$

$3 s ^{2} 3 p ^{3} \rightarrow P$

$3 s ^{2} 3 p ^{4} \rightarrow S$

$C > D > A > B$

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