MCQ
Oxalic acid when reduced with zinc and ${H_2}S{O_4}$ gives
  • A
    Glyoxallic acid
  • B
    Glyoxal
  • Glycollic acid
  • D
    Glycol

Answer

Correct option: C.
Glycollic acid
c
$\underset{\text{Oxalic}\,\,\text{acid}}{\mathop{\begin{matrix}
   COOH  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   COOH  \\
\end{matrix}}}\,\,+\,4\,[H]$ $\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{Zn}}}\,$ $\begin{matrix}
   C{{H}_{2}}OH  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   COOH\,\,  \\
\end{matrix}+{{H}_{2}}O$

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