MCQ
Oxidation number of $C$ in ${C_6}{H_{12}}{O_6}$ is
- A$+ 6$
- B$-6$
- ✓$0$
- D$+4$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{matrix}
CH-C{{O}_{2}}H \\
\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
CH-C{{O}_{2}}H \\
\end{matrix}\xrightarrow[(two\,mole)]{NaOH}(A)\xrightarrow{electrolysis}(B);$