MCQ
Oxidation number of carbon in $\ce{(CN)_2}$ is $.........$
- A$1$
- B$2$
- ✓$3$
- D$4$
✓
Answer
Correct option: C.
$3$
Let $x$ be the oxidation number of $C$ in $\ce{(CN)_2}$.
Since the overall
Charge on the compound is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore, $2(x + (−3)) = 0$ or, $x = +3$
Since the overall
Charge on the compound is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore, $2(x + (−3)) = 0$ or, $x = +3$
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