MCQ
Oxidation number of carbon in ${H_2}{C_2}{O_4}$ is
- A$+4$
- ✓$+3$
- C$+2$
- D$-2$
✓
Answer
Correct option: B.
$+3$
(b) $\mathop {{H_2}{C_2}{O_4}}\limits^ * $
$2 + 2x - 2 \times 4 = 0$; $2x = 8 - 2 = 6$
$x = \frac{6}{2} = + 3$.
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