MCQ
Oxidation number of $Cl$ in $\ce{CaOCl_2}$ is $.........$
  • $−1$ and $+1$
  • B
    $+2$
  • C
    $−2$
  • D
    None of these

Answer

Correct option: A.
$−1$ and $+1$
In $\ce{Ca(OCl)Cl}$, two $Cl$ atoms are in different oxidation state i.e., one $Cl^-$ in $-1$ oxidation state and other as $\ce{OCl^-}$ in $+1$ oxidation state.

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