MCQ
Oxidation number of $N$ in $N{H_3}$ is
- ✓$-3$
- B$+3$
- C$0$
- D$+5$
$x + 3( + 1) = 0$, $x = - 3$.
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$(A)$ $n=4,1=1$ $(B)$ $\mathrm{n}=4,1=2$ $(C)$ $\mathrm{n}=3,1=1$ $(D)$ $\mathrm{n}=3,1=2$ $(E)$ $n=4,1=0$
Choose the correct answer from the options given below:
$C{H_3} - \mathop {\mathop {C = }\limits_{|\,\,\,\,} }\limits_{C{l_{}}\,} \mathop {\mathop {C\, - }\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}\,} \mathop {\mathop {CH - \,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{{C_2}{H_5}\,} C{H_2} - C \equiv CH$
$n$ $l$ $m$ $s$
