MCQ
Oxidation number of oxygen in ${O_2}$ molecule is
- A$+1$
- ✓$0$
- C$+2$
- D$-2$
✓
Answer
Correct option: B.
$0$
(b) Each molecule always show zero oxidation state.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Calculate the heat of formation of $PC{l_5}(s)$ from the following data
→$2P(s) + 3C{l_2}(g)\,\, \to \,\,2PC{l_3}(l);\,\Delta H = - 151.8\,kcal$
$PC{l_3}(l) + C{l_2}(g)\,\, \to \,\,PC{l_5}(s);\,\,\Delta H = - 32.8\,kcal$
......$kcal$
Identify the correct statement about ${H_2}{O_2}$
→Lattice enthalpy and enthalpy of solution of $NaCl$ are $788\, kJ mol ^{-1}$ and $4\, kJ\, mol ^{-1}$ respectively. The hydration enthalpy of $NaCl$ .......$\, kJ\, mol ^{-1}$
→The species which has bond angle 120°
The heat of combustion of $C_xH_y$, carbon and hydrogen are $a, b$ and $c\ cal/mole$ respectively. The heat of formation of $C_xH_y$ will be
→H2SO5 + H2O → H2SO4 + H2O2
Oxidation number of sulphur in H2SO5 in the above reaction is:
Oxidation number of sulphur in H2SO5 in the above reaction is:
Which of following is correct order of electrophilic substitution for given compounds.
Match the conditions and the temperature for the 'fusion' process of $H_2O(s)$ at $1\, atm$ pressure
→| Condition | Temperature |
| $(1)$ Spontaneous | $(p)$ $273\,K$ |
| $(2)$ At equilibrium | $(q)$ $260\, K$ |
| $(3)$ Non-spontaneous | $(r)$ $280\, K$ |
In which of the following does sulphur has the lowest oxidation state?
Calculate the percentage of hydrolysis in $0.01\ M$ aqueous solution of $NaOCN$ ( $K_b$ for $OCN^-= 10^{-10}$ )
→