MCQ
Oxidation number of $S$ in $N{a_2}S{O_4}$ is
- A$-2$
- B$2$
- C$-6$
- ✓$6$
$2 + x - 2 \times 4 = 0$
$x = + 6$.
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Assertion $A$ :$[6]$ Annulene.$[8]$ Annulene and cis - $[10]$ Annulene, are respectively aromatic, not-aromatic and aromatic.
Reason $R$ : Planarity is one of the requirements of aromatic systems.
In the light of the above statements, choose the most appropriate answer from the options given below.
[At. nos. $Zn = 30, Sc = 21, $$Ti = 22, Cr = 24$]