MCQ
Oxidation number of $S$ in ${S_2}C{l_2}$ is
- ✓$+1$
- B$- 1$
- C$+6$
- D$0$
$2x + 2( - 1) = 0$; $2x - 2 = 0$
$x = + 1$.
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$2N_2O_5 \rightarrow 4NO_2 + O_2$ can be written in three ways.
$\frac{-d[N_2O_5 ]}{dt} = k[N_2O_5]$
$\frac{d[NO_2 ]}{dt} = k'[N_2O_5]\,;$ $\frac{d[O_2 ]}{dt} = k"[N_2O_5]$
The relationship between $k$ and $k'$ and betweenk and $k''$ are