- A-2
- B+2
- C+6
- D0
Explanation:
Let Oxidation number of S in S2O32− be x.
Thus,
$2\text{x} + (-2 × 3) = -2 $
$2\text{x} -6 = -2$
$2\text{x} = -2 + 6$
$2\text{x} = 4$
$\text{x}=\frac{4}{2}$
$\text{x}=2$
So the oxidation state of sulfur is +2.
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$\mathop {\mathop C\limits^ \oplus {H_3}}\limits_{(a)} $ $\mathop {\begin{array}{*{20}{c}}
{C{H_2} - \mathop C\limits^ \oplus {H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,F\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}}\limits_{(b)} $ $\mathop {\begin{array}{*{20}{c}}
{C{H_2} - \mathop C\limits^ \oplus {H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}}\limits_{(c)} $ $\mathop {\begin{array}{*{20}{c}}
{C{H_2} - \mathop C\limits^ \oplus {H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}}\limits_{(d)} $
Common name $\to $ $IUPAC$ name