MCQ
Oxidation state of $+ 1$ for phosphorus is found in
- A${H_3}P{O_3}$
- B${H_3}P{O_4}$
- ✓${H_3}P{O_2}$
- D${H_4}{P_2}{O_7}$
$3+x+(-2 \times 2)=0$
$x=+1$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(1)$ $\begin{matrix}
O \\
|| \\
{{C}_{6}}{{H}_{5}}-C-{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$(2)$ $C _{6} H _{5}- CHO$
$(3)$ $p - CH _{3}- C _{6} H _{4}- CHO$
$(4)$ $p - CH _{3} O - C _{6} H _{4}- CHO$
$(A)\, n = 5, m_l= + 1$
$(B)\, n =2, l =1, m_l= -1, m_s = -1/2$
The maximum number of electron$(s)$ in an atom that can have the quantum numbers as given in $(A)$ and $(B)$ are respectively
$(iii)$ $C{H_3} - C(C{H_3})(OH) - C{H_3}$ were treated with Lucas reagent (Conc. $HCl + ZnC{l_2}).$
What results do you expect at room temperature

