MCQ
Oxidation state of $Fe$ in $F{e_3}{O_4}$ is
- A$\frac{3}{2}$
- B$\frac{4}{5}$
- C$\frac{5}{4}$
- ✓$\frac{8}{3}$
✓
Answer
Correct option: D.
$\frac{8}{3}$
(d) $\mathop F\limits^ * {e_3}{O_4}$
$3x + ( - 8) = 0$; $3x - 8 = 0$
$3x = 8$; $x = \frac{8}{3}$.
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