MCQ
Oxidation state of nitrogen in $\ce{NH_2OH}$ is :
- A$−3$
- ✓$−1$
- C$+2$
- D$3$
✓
Answer
Correct option: B.
$−1$
Let $x$ be the oxidation state of $N$ in $\ce{NH_2OH}$.
Since the overall charge on the complex is $0,$ the sum of oxidation states of all elements in it should be equal to $0.$
Therefore, $x + 2 − 1 = 0$ or, $x = −1$.
Since the overall charge on the complex is $0,$ the sum of oxidation states of all elements in it should be equal to $0.$
Therefore, $x + 2 − 1 = 0$ or, $x = −1$.
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