MCQ
Oxidation state of $‘S’ $ in ${H_2}S{O_3}$
- A$+3$
- B$+6$
- ✓$+4$
- D$+2$
$ + 2 + x - 2 \times 3 = 0$; $x = 6 - 2 = + 4$.
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$A$. $\mathrm{Be} \rightarrow \mathrm{Be}^{-}$
$B$. $\mathrm{N} \rightarrow \mathrm{N}^{-}$
$C$. $\mathrm{O} \rightarrow \mathrm{O}^{2-}$
$D$. $\mathrm{Na} \rightarrow \mathrm{Na}^{-}$
$E$. $\mathrm{Al} \rightarrow \mathrm{Al}^{-}$
Choose the most appropriate answer from the options given below :
In the above chemical reaction, intermediate $"X"$ and reagent/condition $"A"$ are