P is a point on side BC of a such that AP bisects . Then, - Vidyadip

MCQ

P is a point on side BC of a $\triangle\text{ABC}$ such that AP bisects $\angle\text{BAC}.$ Then,

A
BP = CP
B
CP < CA
C
BA > BP
D
BP > BA

✓

Answer

BA > BP
Solution:
Since, AP bisects $\angle\text{BAC}.$
Hence the point P on BC also bisects it as it the opposite side of $\angle\text{BAC}.$
Hence, we can conclude that, BA > BP.

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