MCQ
$p- $Nitrobromobenzene can be converted to $p-$nitroaniline by using $NaN{H_2}$. The reaction proceeds through the intermediate named
- ACarbocation
- BCarbanion
- ✓Benzyne
- DDianion

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$(i)$ Methylamine $(ii)$ Phosgene
$(iii)$Phosphine $(iv)$ Dimethylamine
${C_6}{H_5}CHO+X\mathop {\xrightarrow{{(i)\,Zn\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}}\limits_{(ii)\,HOH/N{H_4}Cl} \begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{{C_6}{H_5} - CH - C{H_2} - COO{C_2}{H_5}}
\end{array}$
$[X]$ will be: