Question
$P \rightarrow \sim Q$
$\therefore Q \rightarrow (P\ \&\ Q)$

Answer

Truth Table:
  Support Statement The resulting statement
  $1$ $2$ $3$ $4$ $5$ $6$
$P$ $Q$ $\sim Q$ $P\ \&\ Q$ $P\rightarrow\sim Q$ $Q\rightarrow(P\ \&\ Q)$
$1$ $T$ $T$ $F$ $T$ $F$ $T$
$2$ $T$ $F$ $T$ $F$ $T$ $T$
$3$ $F$ $T$ $F$ $F$ $T^*$ $F^*$
$4$ $F$ $F$ $T$ $F$ $T$ $T$
  $2 (\sim )$ $1, 2(\&)$ $1, 3 (\rightarrow)$ $2, 4 (\rightarrow)$
               
Judgment of the validity of the argument: A total of six columns are presented in the above fact sheet. In which the column no. Base statement and column no. $6$ is the representation of the result statement. Row out of the total four rows of the truth table. The base statement truth in $2, 3$ and $4$ is $‘T’.$ But of the row. The result statement in $3$ is false $‘F’.$ Hence this argument is disproportionate.

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