Question
$P\ v\ Q$
$Q$
$\therefore \sim\ P$

Answer

Combining the two bases of this argument as a whole, the argument will be as follows:
$(P\ v\ Q)\ \&\ Q$
$\therefore \sim P$
Truth Table:
  Support Statement The resulting statement
  $1$ $2$ $3$ $4$ $5$ $6$
$P$ $Q$ $\sim P$ $P\ v\ Q$ $(P\ v\ Q)\ \&\ Q$ $\sim P$
$1$ $T$ $T$ $F$ $T$ $T^*$ $F^*$
$2$ $T$ $F$ $F$ $T$ $F$ $F$
$3$ $F$ $T$ $T$ $T$ $T$ $T$
$4$ $F$ $F$ $T$ $F$ $F$ $T$
  $1 (\sim )$ $1, 2(v)$ $4, 2 (\&)$ As $3$
               
Judgment of the validity of the argument: A total of six columns have been formed in the above fact sheet. In which the column no. Base statement and column no. $6$ is the representation of the result statement. Row out of the total four rows of the truth table. The base statement truth in $1$ and $3$ is $‘T’.$ But of the row. The result statement in $1$ is false $‘F’.$ Hence this argument is disproportionate.

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