MCQ
Pauli's exclusion principle states that
  • A
    Nucleus of an atom contains no negative charge
  • B
    Electrons move in circular orbits around the nucleus
  • C
    Electrons occupy orbitals of lowest energy
  • All the four quantum numbers of two electrons in an atom cannot be equal

Answer

Correct option: D.
All the four quantum numbers of two electrons in an atom cannot be equal
d
(d) According to Pauli’s exclusion principle no two electrons in the same atom can have all the set of four quantum numbers identical.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The $ IUPAC$ name of $C{H_3} - C{H_2} - \mathop {\mathop {C = }\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}} C{H_2}$ is
When $1\,mole$ of $H_2$ and $1\,mole$ of $N_2$ is enclosed in $5\,L$ vessel and the reaction is  allowed to attain equilibrium, it is found that at equilibrium there is $x\,mole$ of $H_2$. The number of moles of $NH_3$ would be
The letter ‘$D$’ in carbohydrates represents
A hydrocarbon containing $2$ carbon atoms gives Sabatier and Senderen's reaction but does not give precipitate with ammoniacal silver nitrate solution. The hydrocarbon in the question is
Which one of the following is an $s$ - block element
Which of the following compound would yield trialkylborane shown below when  treated with $BH_3/THF$?
Match List $I$ with List $II$

LIST $I$ (Technique) LIST $II$ (Application)
$A$. Distillation $I$. Separation of glycerol from spent-lye
$B$. Fractional distillation $II$Aniline - Water mixture
$C$. Steam distillation $III$Separation of crude oil fractions
$D$. Distillation under reduced pressure $IV$.ChloroformAniline

Choose the correct answer from the options given below:

$pH$ of a mixture of $1\ M\ HA (pK_a = 4.2)$ and $1\ M\ NaA$ is $4.5$ . In $300\ ml$ of buffer volume of $HA$ is.......$ml$ $[log\, 2 = 0.3]$
In a constant volume calorimeter, $3.5 \mathrm{~g}$ of a gas with molecular weight $28$ was burnt in excess oxygen at $298.0 \mathrm{~K}$. The temperature of the calorimeter was found to increase from $298.0 \mathrm{~K}$ to $298.45 \mathrm{~K}$ due to the combustion process. Given that the heat capacity of the calorimeter is $2.5 \mathrm{~kJ} \mathrm{~K}^{-1}$, the numerical value for the enthalpy of combustion of the gas in $\mathrm{kJ} \mathrm{mol}^{-1}$ is
Compounds with same molecular formula but different structural formula are called