MCQ
$Pbl_4$ does not exist because
  • A
    iodine is not reactive
  • B
    $Pb(IV)$ is oxidizing and $I^-$ is strong reducing agent
  • $Pb(IV)$ is less stable than $Pb (II)$
  • D
    $Pb^{4+}$ is not easily formed

Answer

Correct option: C.
$Pb(IV)$ is less stable than $Pb (II)$
c
Inert pair effect makes $+2$ as more stable than $+4$ oxidation state

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