MCQ
$Ph - \mathop O\limits^{18} - C{H_3}\xrightarrow{{conc.\,HI}}product$
- ✓$Ph - \mathop O\limits^{18} H$, $CH_3-I$
- B$Ph-I$, $CH_3 \mathop O\limits^{18} H$
- C$Ph-I, CH_3-I$
- D$Ph-OH, CH_3I$
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${C_6}{H_5} - H\mathop {\xrightarrow{{[X]}}}\limits_{AlC{l_3}} $ $\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{C}_{6}}{{H}_{5}}-C-C{{H}_{2}}-{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$[X]$ will be :
Given : $K_b(H_2O) = 0.51\, Kkg \,mol^{-1}$
$N_A = 6 × 10^{23}$
$[Li = 7, \,\,Na = 23$, $K = 39,\,\, Rb = 85.5$ , $Cs = 133, \,\,Cl = 35.5]$
| Observation | $[A]$ | $[B]$ | Rate of reaction |
| $1$ | $0.1$ | $0.1$ | $2 \times {10^{ - 3}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$ |
| $2$ | $0.4$ | $0.1$ | $0.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$ |
| $3$ | $0.1$ | $0.2$ | $1.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$ |