MCQ
$Ph - \mathop O\limits^{18}  - C{H_3}\xrightarrow{{conc.\,HI}}product$
  • $Ph - \mathop O\limits^{18} H$, $CH_3-I$
  • B
    $Ph-I$, $CH_3  \mathop O\limits^{18} H$
  • C
    $Ph-I, CH_3-I$
  • D
    $Ph-OH, CH_3I$

Answer

Correct option: A.
$Ph - \mathop O\limits^{18} H$, $CH_3-I$
a

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

In the reaction :

${C_6}{H_5} - H\mathop {\xrightarrow{{[X]}}}\limits_{AlC{l_3}} $  $\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   {{C}_{6}}{{H}_{5}}-C-C{{H}_{2}}-{{C}_{6}}{{H}_{5}}  \\
\end{matrix}$

$[X]$ will be :

The number of unpaired electrons in the complex ion ${[Co{F_6}]^{3 - }}$ is (Atomic no. of $Co = 27)$
The enthalpy of fusion of water is $1.435\ kcal/mol.$ The molar entropy change for the melting of ice at $0\,^oC$ is
Simultaneous determination of exact position and momentum of an electron is
$pH$ of $HCl\,({10^{ - 12}}M)$ is
When $1.685$ gram of an alkali metal chloride is dissolved in $200$ gram water, the boiling point of the solution is measured to be $100.051\,^o C$. If the ionic solid has a crystal lattice with cation and anion radius $1.70\,\mathop A\limits^o $ and $1.80\,\mathop A\limits^o $ respectively. Find the edge length of solid assuming no defect in the cyrstal -

Given : $K_b(H_2O) = 0.51\, Kkg \,mol^{-1}$

            $N_A = 6 × 10^{23}$

             $[Li = 7, \,\,Na = 23$,  $K = 39,\,\, Rb = 85.5$ , $Cs = 133, \,\,Cl = 35.5]$

Cathode rays are
During an electrolysis of conc. $\ce{H_2SO_4}$, perdisulphuric acid $ (\ce{H_2S_2O_8})$ and $O_2$ form at anode in equimolar amount. The mole of $H_2$ that will form simultaneously at other electrode will be $($Given $\ce{:2H_2SO_4 \rightarrow  H_2S_2O_8 + 2H^+ + 2e^-)}$
What is the order of reaction $A + B \to C$
Observation $[A]$ $[B]$ Rate of reaction
$1$ $0.1$ $0.1$ $2 \times {10^{ - 3}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$
$2$ $0.4$ $0.1$ $0.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$
$3$ $0.1$ $0.2$ $1.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$
$\mathrm{H}_2 \mathrm{~S}$ ($5$ moles) reacts completely with acidified aqueous potassium permanganate solution. In this reaction, the number of moles of water produced is $x$, and the number of moles of electrons involved is $y$. The value of $(x+y)$ is. . . . . .