MCQ
$Ph-Mg-Br + Et-O-Et \rightarrow$ Product will be
- A$Ph-O-et$
- B$Ph-Oh$
- C$Ph-et$
- ✓None
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$\begin{array}{*{20}{c}}
{\,\,O} \\
{\,\,||} \\
{C{H_3} - C - OH}
\end{array}$ $\xrightarrow[\Delta ]{{N{H_3}}}A\,\xrightarrow[\Delta ]{{{P_2}{O_5}'}}B$