MCQ
$Ph - O - C{H_2} - Ph\xrightarrow{{HI}}A + B$ will be
- ✓$Ph -OH + Ph -CH_2 -I$
- B$Ph -I + Ph -CH_2 -I$
- C$Ph -I + Ph -CH_2 -OH$
- D$Ph -OH + Ph -CH_2 -OH$
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$6 \mathrm{OH}^{-}+\mathrm{Cl}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+3 \mathrm{H}_{2} \mathrm{O}+6 \mathrm{e}^{-}$
A current of $x A$ has to be passed for $10 h$ to produce $10.0 \mathrm{~g}$ of potassium chlorate. The value of $\mathrm{x}$ is $.......$ (Nearest integer)
(Molar mass of $\left.\mathrm{KClO}_{3}=122.6 \mathrm{~g} \mathrm{~mol}^{-1}, \mathrm{~F}=96500 \mathrm{C}\right)$