MCQ
$pH$ of a solution can be expressed as
- A$ - {\log _e}({H^ + })$
- ✓$ - {\log _{10}}({H^ + })$
- C${\log _e}({H^ + })$
- D${\log _{10}}({H^ + })$
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$N{H_3} + {H_2}O \to NH_4^ + + O{H^ - }$ is
