MCQ
$pH$ of a solution is $ 4.$ The hydroxide ion concentration of the solution would be
- A${10^{ - 4}}$
- ✓${10^{ - 10}}$
- C${10^{ - 2}}$
- D${10^{ - 12}}$
$pH + pOH = 14$ ; $pOH = 14 - pH$
$pOH = 14 - 4 = 10$; $[O{H^ - }] = {10^{ - 10}}\,M$
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Statement$-I :\, 2 -$methylbutane on oxidation with $KMnO _{4}$ gives $2 -$methylbutan$-2-$ol.
Statement$-II :$ $n-$alkanes can be easily oxidised to corresponding alcohol with $KMnO _{4}$.
Choose the correct option: