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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
$pH + pOH$ equal to
  • A
    Zero
  • ✓
    Fourteen
  • C
    A negative number
  • D
    Infinity
✓

Answer

Correct option: B.
Fourteen
b
- $pH$ is defined as the negative logarithm of Hydrogen ion $\left( H ^{+}\right)$ concentration.

$pH =-\log _{10}\left[ H ^{+}\right]$

- $pOH$ is defined as the negative logarithm of Hydroxide ion $( OH -)$ concentration.

$pOH =-\log _{10}\left[ OH ^{-}\right]$

- The concentration of $\left[ H ^{+}\right]$and $\left[ OH ^{-}\right]$is $10^{-7}$ for a neutral solution.

$pH =-\log _{10}\left[10^{-7}\right]$

$pH =7 \log _{10}[10]$

$pH =7$

$pOH =-\log _{10}\left[10^{-7}\right]$

$pOH =7 \log _{10}[10]$

$pOH =7$

- The value of $\log _{10}[10]$ is $1 .$

- Calculate the sum of $pH$ and $pOH$.

$pH + pOH =7+7$

$=14$

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