MCQ
Phosphine is produced by adding water to
- A$Ca{C_2}$
- B$HP{O_3}$
- ✓$C{a_3}{P_2}$
- D${P_4}{O_{10}}$
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$ + \frac{1}{2}\frac{{d\left[ C \right]}}{{dt}} = - \frac{1}{3}\frac{{d\left[ D \right]}}{{dt}} = + \frac{1}{4}\frac{{d\left[ A \right]}}{{dt}} = \frac{{ - d\left[ B \right]}}{{dt}}$
the reaction is

Considering the above chemical reaction, identify the product $"X"$