MCQ
Phosphorous is having three unpaired electrons according to
- ✓Hund’s rule
- BAufbau principle
- CPauli’s exclusion principle
- DHeisenberg’s principle
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$Gas$ $(A)$ bums with a blue flame and is oxidised to $gas$ $(B)$,
$Gas\left( A \right) + C{l_2} \to \left( D \right)\xrightarrow{{N{H_3},\Delta }}\left( E \right)$.
$A,B, C$ and $E$ are