$\left[ Co \left( NH _{3}\right)_{3}\left( NO _{2}\right)_{3}\right]=$ out of the coordination sphere no ions (non ionisable) $K_{4}\left[F e(C N)_{6}\right]=5$ ions
$\left[ Co \left( NH _{3}\right)_{4}\right] . SO _{4}=2$ ions
More ions $\propto$ more conductivity
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$\frac{{ - d\left[ {{N_2}{O_5}} \right]}}{{dt}} = k\left[ {{N_2}{O_5}} \right]$ ,
$\frac{{d\left[ {N{O_2}} \right]}}{{dt}} = k'\left[ {{N_2}{O_5}} \right]$,
$\frac{{d\left[ {{O_2}} \right]}}{{dt}} = k''\left[ {{N_2}{O_5}} \right]$
The relationship between $k$ and $k'$ and between $k$ and $k^{"}$ are
$(I)$ $CO_2$ $(II)$ $Br_2$ $(III)$ $SnCl_2$ $(IV)$ $HF$ $(V)$ $NMe_3$