MCQ
Picric acid is (at ${25\,^o}C$)
- AA white solid
- BA colourless liquid
- CA gas
- ✓A bright yellow solid
✓
Answer
Correct option: D.
A bright yellow solid
d
It’s Obvious.
It’s Obvious.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$2-$ Hexyne gives trans $-2-$ Hexene on treatment with :
→Which of the following will have geometrical isomers
In the reaction of $p-$ chlorotoluene with $KNH_2$ in liquid $NH_3,$ the major product is :
→The degeneracy of $d-$ orbitals is lost under :
→$(I)$ Strong field ligand $(II)$ Weak field ligand
$(III)$ Mixed field ligand $(IV)$ Chelated ligand field
Choose the correct code
The correct statement(s) for the following addition reactions is(are)
→(IMAGE)
$[A]$ ( $M$ and $O)$ and ( $N$ and $P$ ) are two pairs of diastereomers
$[B]$ Bromination proceeds through trans-addition in both the reactions
$[C]$ $O$ and $P$ are identical molecules
$[D]$ (M and $O)$ and ( $N$ and $P)$ are two pairs of enantiomers
Ignoring specific markings, which of the following objects are chiral ?
$(I)$ a shoe $(II)$ a book $(III)$ a pencil
$(IV)$ a pair of shoes (consider the pair as one object)
$(V)$ a pair of scissors
→$(I)$ a shoe $(II)$ a book $(III)$ a pencil
$(IV)$ a pair of shoes (consider the pair as one object)
$(V)$ a pair of scissors
Formic acid and acetic acid can be distinguished by
In which of the following arrangement the order is not according to the property indicated in bracket
What is the kinetic energy of an electron in second excited state of $He^+$ ?................. $\mathrm{eV}$ (Energy of electron in first shell of $H =\, -\,13.6\, eV$ )
→When a metal rod ${M}$ is dipped into an aqueous colourless concentrated solution of compound ${N}$, the solution turns light blue. Addition of aqueous $\mathrm{NaCl}$ to the blue solution gives a white precipitate ${O}$. Addition of aqueous $\mathrm{NH}_3$ dissolves ${O}$ and gives an intense blue solution.
→$1.$ The metal rod ${M}$ is
$(A)$ $\mathrm{Fe}$ $(B)$ $\mathrm{Cu}$ $(C)$ $\mathrm{Ni}$ $(D)$ $\mathrm{Co}$
$2.$ The compound ${N}$ is
$(A)$ $\mathrm{AgNO}_3$ $(B)$ $\mathrm{Zn}\left(\mathrm{NO}_3\right)_2$
$(C)$ $\mathrm{Al}\left(\mathrm{NO}_3\right)_3$ $(D)$ $\mathrm{Pb}\left(\mathrm{NO}_3\right)_2$
$3.$ The final solution contains
$(A)$ $\left[\mathrm{Pb}\left(\mathrm{NH}_3\right)_4\right]^{2+}$ and $\left[\mathrm{CoCl}_4\right]^{2-}$
$(B)$ $\left[\mathrm{Al}\left(\mathrm{NH}_3\right)_4\right]^{3+}$ and $\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}$
$(C)$ $\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}$and $\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}$
$(D)$ $\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}$and $\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+}$
Give the answer question $1,2$ and $3.$