MCQ
$p{K_a}$ of a weak acid is defined as
- A$log_{10}{K_a}$
- B$\frac{1}{{lo{g_{10}}{K_a}}}$
- ✓$log _{10}\frac{1}{{{K_a}}}$
- D$-log_{10}\frac{1}{{{K_a}}}$
✓
Answer
Correct option: C.
$log _{10}\frac{1}{{{K_a}}}$
(c) $p{K_a} = {\log _{10}}\frac{1}{{{K_a}}}$
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