- ✓They forms soluble complex with cationic species
- BThey forms soluble complex with anionic species
- CThey forms ppt with cationic species.
- DThey forms ppt with anionic species.
It forms a soluble complex with cation and removes the hardness of the water.
The reactions involved are:
$2 CaSO _4+ Na _2\left[ Na _4\left( PO _3\right)_6\right] \rightarrow Na _2\left[ Ca _2\left( PO _3\right)_6\right]+2 Na _2 SO _4$
$2 MgSO _4+ Na _2\left[ Na _4\left( PO _3\right)_6\right] \rightarrow Na _2\left[ Mg _2\left( PO _3\right)_6\right]+2 Na _2 SO _4$
Polyphosphate makes a soluble complex with $Ca ^{+2}$ and $Mg ^{+2}$ and removes the hardness of water caused by calcium sulfate and magnesium sulphate.
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$1.$ $\begin{array}{*{20}{c}}
{C{H_3}C{H_2}CHC{H_3}{\mkern 1mu} } \\
{{\mkern 1mu} \,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\,^ + }N{{(C{H_3})}_3}^ - OH}
\end{array}$ $\xrightarrow{{heat}}$ $\mathop {C{H_3}CH = CHC{H_3}}\limits_X $ $+$ $\mathop {C{H_3}C{H_2}CH = C{H_2}}\limits_Y $
$2.$ $\begin{array}{*{20}{c}}
{C{H_3}C{H_2}CHC{H_3}} \\
{\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,Br}
\end{array}$ $\xrightarrow{{heat}}$ $\mathop {C{H_3}CH = CHC{H_3}}\limits_X $ $+$ $\mathop {C{H_3}C{H_2}CH = C{H_2}}\limits_Y $


If dilute $HCl$ is added to an aqueous solution of ${H_2}S$ without any change in temperature