MCQ
Polyvinylalcohol can be prepared by
- ✓polymerization of vinyl alcohol
- Balkaline hydrolysis of polyvinyl acetate
- Cpolymerization of acetylene
- Dreaction of acetylene with $H_2SO_4$ in presence of $HgSO_4$
✓
Answer
Correct option: A.
polymerization of vinyl alcohol
a
Hydroboration-oxidation leads to anti- Markownikoff’s hydration, thus
Hydroboration-oxidation leads to anti- Markownikoff’s hydration, thus
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In benzene, carbon uses _____ p-orbitals for hybridization.
Choose the chain terminating step
→(1)${H_2} \to {H^ \bullet } + {H^ \bullet }$
(2)$B{r_2} \to B{r^ \bullet } + B{r^ \bullet }$
(3)$B{r^ \bullet } + HBr \to {H^ \bullet } + B{r_2}$
(4)${H^ \bullet } + B{r_2} \to HBr + B{r^ \bullet }$
(5)$B{r^ \bullet } + B{r^ \bullet } \to B{r_2}$
The following equilibrium exists inaqueous solution, $C{H_3}COOH$ $\rightleftharpoons$ $C{H_3}CO{O^ - } + {H^ + }$ if dil $HCl$ is added, without change in temperature, the
→$1\,g$ of a carbonate $\left( M _2 CO _3\right)$ on treatment with excess $HCl$ produces $0.01 mol$ of $CO _2$ The molar mass of $M _2 CO _3$ is $..........\,g\,mol ^{-1}$. (Nearest integer)
→The $pH$ of a ${10^{ - 9}}\,M$ solution of $HCl$ in water is
→If heat of neutralization is $-13.7\, KCal$ at $25\,^oC$ and $\Delta H_f^o (H_2O) = -68\, KCal$ then standard enthalpy of formation of $OH^-$ will be.....$KCal$
→Given two process :
→$\frac{1}{2}{P_4}(s) + 3C{l_2}(g) \to 2PC{l_3}(l)\,;$ $\Delta H=-635 \,kJ$
$PC{l_3}(l) + C{l_2}(g) \to PC{l_5}(s)\,;$ $\Delta H=-137\, kJ$
The value of heat of formation of $PCl_5$ is ......$kJ\,mol^{-1}$
In the given reaction $3-$Bromo$-2,2-$dimethyl butane
→${\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}}{\longrightarrow} {\text { (Major product) }{ }^{\prime} \mathrm{A}^{\prime}}$
Product $A$ is :
What will be de-Broglie wavelength of an electron moving with a velocity of $1.2 \times {10^5}\,m{s^{ - 1}}$
→$100\,\,ml$ of $0.2\,\,M\,\,{H_2}S{O_4}$ is added to $100\,\,ml$ of $0.2\,\,M\,\,NaOH.$ The resulting solution will be
→