MCQ
Potential energy of electron present in $He^+$ is
  • A
    $\frac{{{e^2}}}{{2\pi { \in _0}r}}$
  • B
    $\frac{{3{e^2}}}{{4\pi { \in _0}r}}$
  • $\frac{{ - {e^2}}}{{2\pi { \in _0}r}}$
  • D
    $\frac{{ - {e^2}}}{{4\pi { \in _0}{r^2}}}$

Answer

Correct option: C.
$\frac{{ - {e^2}}}{{2\pi { \in _0}r}}$
c
$P.E.$ = $ - \frac{{KZ{e^2}}}{r} = \frac{{ - 1}}{{4\pi { \in _0}}} \times \frac{{2{e^2}}}{r} =  - \frac{{{e^2}}}{{2\pi { \in _0}r}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The compound$(s)$ that exhibit$(s)$ geometrical isomerism is$(are)$

$(A)$ $\left[\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_2\right]$ $(B)$ $\left[\mathrm{Pt}(\mathrm{en})_2\right] \mathrm{Cl}_2$

$(C)$ $\left[\mathrm{Pt}(\text { en })_2 \mathrm{Cl}_2\right] \mathrm{Cl}_2$ $(D)$ $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$

If lone pair of electron occupy axial position then incorrect about $ClF_3$ is
The orbital picture of a singlet carbene $(:CH_2)$ can be drawn as
$P$ and $Q$ are isomers of dicarboxylic acid $C _4 H _4 O _4$. Both decolorize $Br _2 / H _2 O$. On heating, $P$ forms the cyclic anhydride.

Upon treatment with dilute alkaline $KMnO _4, P$ as well as $Q$ could produce one or more than one from $S , T$ and $U$.$Image$

$1.$ Compounds formed form $P$ and $Q$ are, respectively

$(A)$ Optically active $S$ and optically active pair $(T, U)$

$(B)$ Optically inactive $S$ and optically inactive pair $(T, U)$

$(C)$ Optically active pair $(T, U)$ and optically active $S$

$(D)$ Optically inactive pair $(T, U)$ and optically inactive $S$

$2.$ In the following reaction sequences $V$ and $W$ are respectively :$Image$

mcq $Image$

Give the answer question $1$ and $2.$

Which of the following is not a transition metal?
Which alkyl halide has maximum density ?
Which of the followings is most reactive toward hydrolysis
When glycerol is treated with excess of $HI$, it produces
Stability order of following carbocation is :

$(i)$ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}-CH_2} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - {C^ + }} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(ii)$  $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - {C^ + }} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{H}} 
\end{array}$

$(iii)$ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - {C^ + }} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(iv)$ $Ph - CH ^{+}-\underline{ CH }_{3}$ 

The rate of $o-$ nitration of the above compounds, $(I)$ toluene, $(II)\, 2-D-$ toluene and $(III) \,2, 6-D_2$ -toluene is in the following order