MCQ
Predict the product in the given reaction
- A
- B
- ✓
- D
✓
Answer
Correct option: C.
c
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$a. (\text{CH}_{3})_{2}\text{CH}-\text{CH}-\text{COOH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{NH}_{2}$
$b. \text{HOOC}-\text{CH}_{2}-\text{CH}_{2}-\text{CH}-\text{COOH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{NH}_{2}\\ \ \ \ \ \ $
$c. \text{H}_{2}\text{N}-\text{CH}_{2}-\text{CH}_{2}-\text{CH}_{2}-\text{COOH}$
$d. \text{HOOC}-\text{CH}_{2}-\text{CH}-\text{COOH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{NH}_{2}\\ \ \ \ \ \ $
→$a. (\text{CH}_{3})_{2}\text{CH}-\text{CH}-\text{COOH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{NH}_{2}$
$b. \text{HOOC}-\text{CH}_{2}-\text{CH}_{2}-\text{CH}-\text{COOH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{NH}_{2}\\ \ \ \ \ \ $
$c. \text{H}_{2}\text{N}-\text{CH}_{2}-\text{CH}_{2}-\text{CH}_{2}-\text{COOH}$
$d. \text{HOOC}-\text{CH}_{2}-\text{CH}-\text{COOH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{NH}_{2}\\ \ \ \ \ \ $
$B\mathop {\xleftarrow{{C{H_3}OH}}}\limits_{C{H_3}ONa} $ $[Figure]$ $\mathop {\xrightarrow{{{H_2}{O^{18}}}}}\limits_{{H^ + }} A$
→$A$ and $B$ are
${\lambda _{ClC{H_2}COONa}} = 224\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,
→${\lambda _{NaCl}} = 38.2\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,
${\lambda _{HCl}} = 203\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,
What is the value of ${\lambda _{ClC{H_2}COOH}}$ .............. ${\rm{Oh}}{{\rm{m}}^{ - 1}}{\mkern 1mu} {\rm{c}}{{\rm{m}}^2}{\rm{gm}}\,{\rm{e}}{{\rm{q}}^{ - 1}}$
When $D-$ glucose is treated with $Br_2$ water then the product is :
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