MCQ
Primary alcohol is mainly formed in
  • A
    $C{H_3} - CH = C{H_2}\,\xrightarrow{{{H_3}{O^ \oplus }}}$
  • B
    $C{H_3} - CH = O\xrightarrow[{(2)\,\,{H_2}O}]{{(1)\,\,C{H_3}MgBr}}$
  • $C{H_3} - CH = C{H_2}\xrightarrow[{(2)\,\,{H_2}{O_2}/\mathop O\limits^\Theta  H(aq.)}]{{(1)\,\,B{H_3},THF}}$
  • D
    None

Answer

Correct option: C.
$C{H_3} - CH = C{H_2}\xrightarrow[{(2)\,\,{H_2}{O_2}/\mathop O\limits^\Theta  H(aq.)}]{{(1)\,\,B{H_3},THF}}$
c

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