MCQ
Product $(A)$ is


- A

- ✓

- C

- D








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In the given reaction what will be the product

$\left[\right.$ Given $\left.: \log _{10} 2=0.301, \ln 10=2.303\right]$

The product is :-
| $I$ | $II$ | |
| $[Cr(H_2O)_6]^{+2}$ | $[Cr(H_2O)_6]^{+3}$ | $(a)$ |
| $[Fe(H_2O)_6]^{+3}$ | $[Fe(CN)_6]^{-3}$ | $(b)$ |
| $[Fe(CN)_6]^{+3}$ | $[Ru(CN)_6]^{-3}$ | $(c)$ |
| $[NiF_6]^{-4}$ | $[NiF_6]^{-2}$ | $(d)$ |